Base | Representation |
---|---|
bin | 1011001101110001101110… |
… | …0011010001111011100010 |
3 | 1121122212021102120121212201 |
4 | 2303130123203101323202 |
5 | 3104014012203341010 |
6 | 42120532132443414 |
7 | 2411623303644601 |
oct | 263343343217342 |
9 | 47585242517781 |
10 | 12331313340130 |
11 | 3a247539a3aa4 |
12 | 1471a83a7956a |
13 | 6b5ab7a0c505 |
14 | 308ba575da38 |
15 | 165b7468123a |
hex | b371b8d1ee2 |
12331313340130 has 16 divisors (see below), whose sum is σ = 22200022661760. Its totient is φ = 4931712302832.
The previous prime is 12331313340121. The next prime is 12331313340131. The reversal of 12331313340130 is 3104331313321.
It is a super-2 number, since 2×123313133401302 (a number of 27 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (12331313340131) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 101565450 + ... + 101686789.
It is an arithmetic number, because the mean of its divisors is an integer number (1387501416360).
Almost surely, 212331313340130 is an apocalyptic number.
12331313340130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
12331313340130 is a deficient number, since it is larger than the sum of its proper divisors (9868709321630).
12331313340130 is a wasteful number, since it uses less digits than its factorization.
12331313340130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 203258313.
The product of its (nonzero) digits is 5832, while the sum is 28.
Adding to 12331313340130 its reverse (3104331313321), we get a palindrome (15435644653451).
The spelling of 12331313340130 in words is "twelve trillion, three hundred thirty-one billion, three hundred thirteen million, three hundred forty thousand, one hundred thirty".
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