Base | Representation |
---|---|
bin | 1011001101110001101110… |
… | …0011010001111011101011 |
3 | 1121122212021102120121220001 |
4 | 2303130123203101323223 |
5 | 3104014012203341024 |
6 | 42120532132443431 |
7 | 2411623303644613 |
oct | 263343343217353 |
9 | 47585242517801 |
10 | 12331313340139 |
11 | 3a247539a4002 |
12 | 1471a83a79577 |
13 | 6b5ab7a0c511 |
14 | 308ba575da43 |
15 | 165b74681244 |
hex | b371b8d1eeb |
12331313340139 has 2 divisors, whose sum is σ = 12331313340140. Its totient is φ = 12331313340138.
The previous prime is 12331313340131. The next prime is 12331313340179. The reversal of 12331313340139 is 93104331313321.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12331313340139 - 23 = 12331313340131 is a prime.
It is a super-2 number, since 2×123313133401392 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 12331313340098 and 12331313340107.
It is not a weakly prime, because it can be changed into another prime (12331313340131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6165656670069 + 6165656670070.
It is an arithmetic number, because the mean of its divisors is an integer number (6165656670070).
Almost surely, 212331313340139 is an apocalyptic number.
12331313340139 is a deficient number, since it is larger than the sum of its proper divisors (1).
12331313340139 is an equidigital number, since it uses as much as digits as its factorization.
12331313340139 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 52488, while the sum is 37.
The spelling of 12331313340139 in words is "twelve trillion, three hundred thirty-one billion, three hundred thirteen million, three hundred forty thousand, one hundred thirty-nine".
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