Base | Representation |
---|---|
bin | 11100000010011100011000… |
… | …001101100001000101110011 |
3 | 121011121121221210010021020111 |
4 | 130002130120031201011303 |
5 | 112130330424312411201 |
6 | 1114133150241322151 |
7 | 34655041232402602 |
oct | 3402343015410563 |
9 | 534547853107214 |
10 | 123313212232051 |
11 | 36322926599726 |
12 | 119b6b15336357 |
13 | 53a6503107c5a |
14 | 2264569abba39 |
15 | e3c9d642db51 |
hex | 702718361173 |
123313212232051 has 2 divisors, whose sum is σ = 123313212232052. Its totient is φ = 123313212232050.
The previous prime is 123313212232039. The next prime is 123313212232103. The reversal of 123313212232051 is 150232212313321.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-123313212232051 is a prime.
It is a super-2 number, since 2×1233132122320512 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (123313212230051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61656606116025 + 61656606116026.
It is an arithmetic number, because the mean of its divisors is an integer number (61656606116026).
Almost surely, 2123313212232051 is an apocalyptic number.
123313212232051 is a deficient number, since it is larger than the sum of its proper divisors (1).
123313212232051 is an equidigital number, since it uses as much as digits as its factorization.
123313212232051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12960, while the sum is 31.
Adding to 123313212232051 its reverse (150232212313321), we get a palindrome (273545424545372).
The spelling of 123313212232051 in words is "one hundred twenty-three trillion, three hundred thirteen billion, two hundred twelve million, two hundred thirty-two thousand, fifty-one".
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