Base | Representation |
---|---|
bin | 11100000010011101011011… |
… | …101000101101100101110001 |
3 | 121011121201212121200022102112 |
4 | 130002131123220231211301 |
5 | 112130340233404401414 |
6 | 1114133454411055105 |
7 | 34655111246433335 |
oct | 3402353350554561 |
9 | 534551777608375 |
10 | 123314343434609 |
11 | 36323357085978 |
12 | 119b7190141495 |
13 | 53a6653592092 |
14 | 226463601d7c5 |
15 | e3ca508c9d3e |
hex | 70275ba2d971 |
123314343434609 has 2 divisors, whose sum is σ = 123314343434610. Its totient is φ = 123314343434608.
The previous prime is 123314343434591. The next prime is 123314343434617. The reversal of 123314343434609 is 906434343413321.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 68750962224400 + 54563381210209 = 8291620^2 + 7386703^2 .
It is a cyclic number.
It is not a de Polignac number, because 123314343434609 - 220 = 123314342386033 is a prime.
It is not a weakly prime, because it can be changed into another prime (123314343434209) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61657171717304 + 61657171717305.
It is an arithmetic number, because the mean of its divisors is an integer number (61657171717305).
Almost surely, 2123314343434609 is an apocalyptic number.
It is an amenable number.
123314343434609 is a deficient number, since it is larger than the sum of its proper divisors (1).
123314343434609 is an equidigital number, since it uses as much as digits as its factorization.
123314343434609 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6718464, while the sum is 50.
The spelling of 123314343434609 in words is "one hundred twenty-three trillion, three hundred fourteen billion, three hundred forty-three million, four hundred thirty-four thousand, six hundred nine".
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