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123314410542137 is a prime number
BaseRepresentation
bin11100000010011101011111…
…101000101101010000111001
3121011121202001021221201122112
4130002131133220231100321
5112130340403044322022
61114133505205302105
734655113023022163
oct3402353750552071
9534552037851575
10123314410542137
1136323390a50841
12119b71aa704935
1353a666445a189
142264640ccb933
15e3ca567338e2
hex70275fa2d439

123314410542137 has 2 divisors, whose sum is σ = 123314410542138. Its totient is φ = 123314410542136.

The previous prime is 123314410542107. The next prime is 123314410542149. The reversal of 123314410542137 is 731245014413321.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 74986178215936 + 48328232326201 = 8659456^2 + 6951851^2 .

It is a cyclic number.

It is not a de Polignac number, because 123314410542137 - 212 = 123314410538041 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 123314410542094 and 123314410542103.

It is not a weakly prime, because it can be changed into another prime (123314410542107) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61657205271068 + 61657205271069.

It is an arithmetic number, because the mean of its divisors is an integer number (61657205271069).

Almost surely, 2123314410542137 is an apocalyptic number.

It is an amenable number.

123314410542137 is a deficient number, since it is larger than the sum of its proper divisors (1).

123314410542137 is an equidigital number, since it uses as much as digits as its factorization.

123314410542137 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 241920, while the sum is 41.

Adding to 123314410542137 its reverse (731245014413321), we get a palindrome (854559424955458).

The spelling of 123314410542137 in words is "one hundred twenty-three trillion, three hundred fourteen billion, four hundred ten million, five hundred forty-two thousand, one hundred thirty-seven".