1233213101233 has 4 divisors (see below), whose sum is σ = 1237103363700. Its totient is φ = 1229322838768.

The previous prime is 1233213101089. The next prime is 1233213101249. The reversal of 1233213101233 is 3321013123321.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 688189703184 + 545023398049 = 829572^2 + 738257^2 .

It is a cyclic number.

It is not a de Polignac number, because 1233213101233 - 2²⁹ = 1232676230321 is a prime.

It is a super-2 number, since 2×1233213101233² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1233213101198 and 1233213101207.

It is not an unprimeable number, because it can be changed into a prime (1233213101033) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1945130758 + ... + 1945131391.

It is an arithmetic number, because the mean of its divisors is an integer number (309275840925).

Almost surely, 2^{1233213101233} is an apocalyptic number.

It is an amenable number.

1233213101233 is a deficient number, since it is larger than the sum of its proper divisors (3890262467).

1233213101233 is an equidigital number, since it uses as much as digits as its factorization.

1233213101233 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3890262466.

The product of its (nonzero) digits is 1944, while the sum is 25.

Adding to 1233213101233 its reverse (3321013123321), we get a palindrome (4554226224554).

The spelling of 1233213101233 in words is "one trillion, two hundred thirty-three billion, two hundred thirteen million, one hundred one thousand, two hundred thirty-three".