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123332315201131 is a prime number
BaseRepresentation
bin11100000010101110001010…
…110101100011111001101011
3121011200110021002201122101211
4130002232022311203321223
5112131134040142414011
61114150030004253551
734656315513065161
oct3402561265437153
9534613232648354
10123332315201131
113632aa39734083
12119ba7669a12b7
1353a82589b875a
14226545cbbb231
15e3d253557b21
hex702b8ad63e6b

123332315201131 has 2 divisors, whose sum is σ = 123332315201132. Its totient is φ = 123332315201130.

The previous prime is 123332315201107. The next prime is 123332315201171. The reversal of 123332315201131 is 131102513233321.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 123332315201131 - 225 = 123332281646699 is a prime.

It is a super-2 number, since 2×1233323152011312 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 123332315201093 and 123332315201102.

It is not a weakly prime, because it can be changed into another prime (123332315201171) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61666157600565 + 61666157600566.

It is an arithmetic number, because the mean of its divisors is an integer number (61666157600566).

Almost surely, 2123332315201131 is an apocalyptic number.

123332315201131 is a deficient number, since it is larger than the sum of its proper divisors (1).

123332315201131 is an equidigital number, since it uses as much as digits as its factorization.

123332315201131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9720, while the sum is 31.

Adding to 123332315201131 its reverse (131102513233321), we get a palindrome (254434828434452).

The spelling of 123332315201131 in words is "one hundred twenty-three trillion, three hundred thirty-two billion, three hundred fifteen million, two hundred one thousand, one hundred thirty-one".