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123333216113 is a prime number
BaseRepresentation
bin111001011011100111…
…0111000011101110001
3102210100022012112102002
41302313032320131301
54010041300403423
6132354122503345
711624212016432
oct1626716703561
9383308175362
10123333216113
114833a426788
121baa0064b55
13b8269294b3
145d7dccb489
15331c91a228
hex1cb73b8771

123333216113 has 2 divisors, whose sum is σ = 123333216114. Its totient is φ = 123333216112.

The previous prime is 123333216091. The next prime is 123333216137. The reversal of 123333216113 is 311612333321.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 115730596864 + 7602619249 = 340192^2 + 87193^2 .

It is an emirp because it is prime and its reverse (311612333321) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 123333216113 - 212 = 123333212017 is a prime.

It is a super-2 number, since 2×1233332161132 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (123333216163) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61666608056 + 61666608057.

It is an arithmetic number, because the mean of its divisors is an integer number (61666608057).

Almost surely, 2123333216113 is an apocalyptic number.

It is an amenable number.

123333216113 is a deficient number, since it is larger than the sum of its proper divisors (1).

123333216113 is an equidigital number, since it uses as much as digits as its factorization.

123333216113 is an evil number, because the sum of its binary digits is even.

The product of its digits is 5832, while the sum is 29.

Adding to 123333216113 its reverse (311612333321), we get a palindrome (434945549434).

The spelling of 123333216113 in words is "one hundred twenty-three billion, three hundred thirty-three million, two hundred sixteen thousand, one hundred thirteen".