123333243350145 has 32 divisors (see below), whose sum is σ = 198053197345152. Its totient is φ = 65537745388032.

The previous prime is 123333243350131. The next prime is 123333243350159. The reversal of 123333243350145 is 541053342333321.

It is an interprime number because it is at equal distance from previous prime (123333243350131) and next prime (123333243350159).

It is not a de Polignac number, because 123333243350145 - 2⁴ = 123333243350129 is a prime.

It is a super-3 number, since 3×123333243350145³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 123333243350097 and 123333243350106.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 110102854 + ... + 111217376.

It is an arithmetic number, because the mean of its divisors is an integer number (6189162417036).

Almost surely, 2^{123333243350145} is an apocalyptic number.

123333243350145 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

It is an amenable number.

123333243350145 is a deficient number, since it is larger than the sum of its proper divisors (74719953995007).

123333243350145 is a wasteful number, since it uses less digits than its factorization.

123333243350145 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1141441.

The product of its (nonzero) digits is 1166400, while the sum is 42.

Adding to 123333243350145 its reverse (541053342333321), we get a palindrome (664386585683466).

The spelling of 123333243350145 in words is "one hundred twenty-three trillion, three hundred thirty-three billion, two hundred forty-three million, three hundred fifty thousand, one hundred forty-five".