123335413433 has 2 divisors, whose sum is σ = 123335413434. Its totient is φ = 123335413432.

The previous prime is 123335413427. The next prime is 123335413477. The reversal of 123335413433 is 334314533321.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 100215298624 + 23120114809 = 316568^2 + 152053^2 .

It is a cyclic number.

It is not a de Polignac number, because 123335413433 - 2¹⁴ = 123335397049 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 123335413393 and 123335413402.

It is not a weakly prime, because it can be changed into another prime (123335413633) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61667706716 + 61667706717.

It is an arithmetic number, because the mean of its divisors is an integer number (61667706717).

Almost surely, 2^123335413433 is an apocalyptic number.

It is an amenable number.

123335413433 is a deficient number, since it is larger than the sum of its proper divisors (1).

123335413433 is an equidigital number, since it uses as much as digits as its factorization.

123335413433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 116640, while the sum is 35.

Adding to 123335413433 its reverse (334314533321), we get a palindrome (457649946754).

The spelling of 123335413433 in words is "one hundred twenty-three billion, three hundred thirty-five million, four hundred thirteen thousand, four hundred thirty-three".