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12334034113 is a prime number
BaseRepresentation
bin10110111110010101…
…00110110011000001
31011211120122212000021
423133022212303001
5200230003042423
65355521053441
7614435363062
oct133712466301
934746585007
1012334034113
11525a271425
122482787281
13121741a84b
14850130569
154c2c5395d
hex2df2a6cc1

12334034113 has 2 divisors, whose sum is σ = 12334034114. Its totient is φ = 12334034112.

The previous prime is 12334034107. The next prime is 12334034131. The reversal of 12334034113 is 31143043321.

Together with next prime (12334034131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8849729329 + 3484304784 = 94073^2 + 59028^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12334034113 is a prime.

It is not a weakly prime, because it can be changed into another prime (12334037113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6167017056 + 6167017057.

It is an arithmetic number, because the mean of its divisors is an integer number (6167017057).

Almost surely, 212334034113 is an apocalyptic number.

It is an amenable number.

12334034113 is a deficient number, since it is larger than the sum of its proper divisors (1).

12334034113 is an equidigital number, since it uses as much as digits as its factorization.

12334034113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 12334034113 its reverse (31143043321), we get a palindrome (43477077434).

The spelling of 12334034113 in words is "twelve billion, three hundred thirty-four million, thirty-four thousand, one hundred thirteen".