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123345341143403 = 569553121656513
BaseRepresentation
bin11100000010111010010011…
…001111100101100101101011
3121011201200212220100001222012
4130002322103033211211223
5112131342224313042103
61114200022323350135
734660256352551231
oct3402722317454553
9534650786301865
10123345341143403
1136335513518325
1211a011a122234b
1353a95535714c2
142265d36b7a951
15e3d766dd12d8
hex702e933e596b

123345341143403 has 4 divisors (see below), whose sum is σ = 123345368495448. Its totient is φ = 123345313791360.

The previous prime is 123345341143369. The next prime is 123345341143411. The reversal of 123345341143403 is 304341143543321.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 123345341143403 - 28 = 123345341143147 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (123345341143483) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5132726 + ... + 16523787.

It is an arithmetic number, because the mean of its divisors is an integer number (30836342123862).

Almost surely, 2123345341143403 is an apocalyptic number.

123345341143403 is a deficient number, since it is larger than the sum of its proper divisors (27352045).

123345341143403 is an equidigital number, since it uses as much as digits as its factorization.

123345341143403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 27352044.

The product of its (nonzero) digits is 622080, while the sum is 41.

Adding to 123345341143403 its reverse (304341143543321), we get a palindrome (427686484686724).

The spelling of 123345341143403 in words is "one hundred twenty-three trillion, three hundred forty-five billion, three hundred forty-one million, one hundred forty-three thousand, four hundred three".

Divisors: 1 5695531 21656513 123345341143403