Base | Representation |
---|---|
bin | 1011001110010010101010… |
… | …0111011110110010111011 |
3 | 1121200201002200200000202210 |
4 | 2303210222213132302323 |
5 | 3104140114421043420 |
6 | 42124553414230203 |
7 | 2412355366420101 |
oct | 263445247366273 |
9 | 47621080600683 |
10 | 12340156034235 |
11 | 3a28481412a57 |
12 | 1473731355363 |
13 | 6b6896a033a3 |
14 | 3093a3d07c71 |
15 | 165ee0b389e0 |
hex | b392a9decbb |
12340156034235 has 16 divisors (see below), whose sum is σ = 20277878024736. Its totient is φ = 6403540428288.
The previous prime is 12340156034189. The next prime is 12340156034251. The reversal of 12340156034235 is 53243065104321.
It is not a de Polignac number, because 12340156034235 - 211 = 12340156032187 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12340156034193 and 12340156034202.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 11117257134 + ... + 11117258243.
It is an arithmetic number, because the mean of its divisors is an integer number (1267367376546).
Almost surely, 212340156034235 is an apocalyptic number.
12340156034235 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
12340156034235 is a deficient number, since it is larger than the sum of its proper divisors (7937721990501).
12340156034235 is a wasteful number, since it uses less digits than its factorization.
12340156034235 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 22234515422.
The product of its (nonzero) digits is 259200, while the sum is 39.
The spelling of 12340156034235 in words is "twelve trillion, three hundred forty billion, one hundred fifty-six million, thirty-four thousand, two hundred thirty-five".
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