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12340156034235 = 353722234515377
BaseRepresentation
bin1011001110010010101010…
…0111011110110010111011
31121200201002200200000202210
42303210222213132302323
53104140114421043420
642124553414230203
72412355366420101
oct263445247366273
947621080600683
1012340156034235
113a28481412a57
121473731355363
136b6896a033a3
143093a3d07c71
15165ee0b389e0
hexb392a9decbb

12340156034235 has 16 divisors (see below), whose sum is σ = 20277878024736. Its totient is φ = 6403540428288.

The previous prime is 12340156034189. The next prime is 12340156034251. The reversal of 12340156034235 is 53243065104321.

It is not a de Polignac number, because 12340156034235 - 211 = 12340156032187 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12340156034193 and 12340156034202.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 11117257134 + ... + 11117258243.

It is an arithmetic number, because the mean of its divisors is an integer number (1267367376546).

Almost surely, 212340156034235 is an apocalyptic number.

12340156034235 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

12340156034235 is a deficient number, since it is larger than the sum of its proper divisors (7937721990501).

12340156034235 is a wasteful number, since it uses less digits than its factorization.

12340156034235 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 22234515422.

The product of its (nonzero) digits is 259200, while the sum is 39.

The spelling of 12340156034235 in words is "twelve trillion, three hundred forty billion, one hundred fifty-six million, thirty-four thousand, two hundred thirty-five".

Divisors: 1 3 5 15 37 111 185 555 22234515377 66703546131 111172576885 333517730655 822677068949 2468031206847 4113385344745 12340156034235