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123403132113 = 341134377371
BaseRepresentation
bin111001011101101100…
…1100101110011010001
3102210112011202122010120
41302323121211303101
54010212200211423
6132405101220453
711626021213242
oct1627331456321
9383464678116
10123403132113
114837593a6a8
121babb561729
13b838268a01
145d892cacc9
153323b2aee3
hex1cbb665cd1

123403132113 has 4 divisors (see below), whose sum is σ = 164537509488. Its totient is φ = 82268754740.

The previous prime is 123403132079. The next prime is 123403132117. The reversal of 123403132113 is 311231304321.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 123403132113 - 217 = 123403001041 is a prime.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (123403132117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20567188683 + ... + 20567188688.

It is an arithmetic number, because the mean of its divisors is an integer number (41134377372).

Almost surely, 2123403132113 is an apocalyptic number.

It is an amenable number.

123403132113 is a deficient number, since it is larger than the sum of its proper divisors (41134377375).

123403132113 is an equidigital number, since it uses as much as digits as its factorization.

123403132113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 41134377374.

The product of its (nonzero) digits is 1296, while the sum is 24.

Adding to 123403132113 its reverse (311231304321), we get a palindrome (434634436434).

The spelling of 123403132113 in words is "one hundred twenty-three billion, four hundred three million, one hundred thirty-two thousand, one hundred thirteen".

Divisors: 1 3 41134377371 123403132113