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12340433 = 71762919
BaseRepresentation
bin101111000100…
…110011010001
3212012221220002
4233010303101
511124343213
61120255345
7206614640
oct57046321
925187802
1012340433
116a69606
124171555
132730c41
1418d3357
15113b658
hexbc4cd1

12340433 has 4 divisors (see below), whose sum is σ = 14103360. Its totient is φ = 10577508.

The previous prime is 12340429. The next prime is 12340459. The reversal of 12340433 is 33404321.

12340433 is digitally balanced in base 2 and base 8, because in such bases it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12340433 - 22 = 12340429 is a prime.

It is a Duffinian number.

12340433 is strictly pandigital in base 8.

It is not an unprimeable number, because it can be changed into a prime (12340403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 881453 + ... + 881466.

It is an arithmetic number, because the mean of its divisors is an integer number (3525840).

Almost surely, 212340433 is an apocalyptic number.

It is an amenable number.

12340433 is a deficient number, since it is larger than the sum of its proper divisors (1762927).

12340433 is an equidigital number, since it uses as much as digits as its factorization.

12340433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1762926.

The product of its (nonzero) digits is 864, while the sum is 20.

The square root of 12340433 is about 3512.8952446664. The cubic root of 12340433 is about 231.0876837093.

Adding to 12340433 its reverse (33404321), we get a palindrome (45744754).

The spelling of 12340433 in words is "twelve million, three hundred forty thousand, four hundred thirty-three".

Divisors: 1 7 1762919 12340433