Base | Representation |
---|---|
bin | 111001011101111111… |
… | …1110011111011100001 |
3 | 102210112212121200002101 |
4 | 1302323333303323201 |
5 | 4010222231321312 |
6 | 132410100050401 |
7 | 11626202323201 |
oct | 1627377637341 |
9 | 383485550071 |
10 | 123413151457 |
11 | 48380563352 |
12 | 1bb02993a01 |
13 | b83a36630b |
14 | 5d8a778401 |
15 | 3324959a57 |
hex | 1cbbff3ee1 |
123413151457 has 2 divisors, whose sum is σ = 123413151458. Its totient is φ = 123413151456.
The previous prime is 123413151409. The next prime is 123413151467. The reversal of 123413151457 is 754151314321.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 76591116001 + 46822035456 = 276751^2 + 216384^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-123413151457 is a prime.
It is not a weakly prime, because it can be changed into another prime (123413151467) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61706575728 + 61706575729.
It is an arithmetic number, because the mean of its divisors is an integer number (61706575729).
Almost surely, 2123413151457 is an apocalyptic number.
It is an amenable number.
123413151457 is a deficient number, since it is larger than the sum of its proper divisors (1).
123413151457 is an equidigital number, since it uses as much as digits as its factorization.
123413151457 is an evil number, because the sum of its binary digits is even.
The product of its digits is 50400, while the sum is 37.
Adding to 123413151457 its reverse (754151314321), we get a palindrome (877564465778).
The spelling of 123413151457 in words is "one hundred twenty-three billion, four hundred thirteen million, one hundred fifty-one thousand, four hundred fifty-seven".
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