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123417255131 is a prime number
BaseRepresentation
bin111001011110000111…
…1011101110011011011
3102210120011100011021022
41302330033131303123
54010224304131011
6132410324033055
711626252234232
oct1627417356333
9383504304238
10123417255131
1148382906515
121bb0423278b
13b83b172121
145d8b125b19
153324eba8db
hex1cbc3ddcdb

123417255131 has 2 divisors, whose sum is σ = 123417255132. Its totient is φ = 123417255130.

The previous prime is 123417255127. The next prime is 123417255179. The reversal of 123417255131 is 131552714321.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 123417255131 - 22 = 123417255127 is a prime.

It is a super-2 number, since 2×1234172551312 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 123417255091 and 123417255100.

It is not a weakly prime, because it can be changed into another prime (123417225131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61708627565 + 61708627566.

It is an arithmetic number, because the mean of its divisors is an integer number (61708627566).

Almost surely, 2123417255131 is an apocalyptic number.

123417255131 is a deficient number, since it is larger than the sum of its proper divisors (1).

123417255131 is an equidigital number, since it uses as much as digits as its factorization.

123417255131 is an evil number, because the sum of its binary digits is even.

The product of its digits is 25200, while the sum is 35.

Adding to 123417255131 its reverse (131552714321), we get a palindrome (254969969452).

The spelling of 123417255131 in words is "one hundred twenty-three billion, four hundred seventeen million, two hundred fifty-five thousand, one hundred thirty-one".