Base | Representation |
---|---|
bin | 11100000100000010111111… |
… | …111011101010000111101011 |
3 | 121012000011100222102100101012 |
4 | 130010002333323222013223 |
5 | 112134132110434231011 |
6 | 1114255532150214135 |
7 | 34666021626514223 |
oct | 3404027773520753 |
9 | 535004328370335 |
10 | 123423400305131 |
11 | 3636562a915933 |
12 | 11a1434705434b |
13 | 53b3a135744b4 |
14 | 2269a1dc5b083 |
15 | e407d4cc6a8b |
hex | 7040bfeea1eb |
123423400305131 has 2 divisors, whose sum is σ = 123423400305132. Its totient is φ = 123423400305130.
The previous prime is 123423400305119. The next prime is 123423400305203. The reversal of 123423400305131 is 131503004324321.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-123423400305131 is a prime.
It is a super-2 number, since 2×1234234003051312 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (123423400305431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61711700152565 + 61711700152566.
It is an arithmetic number, because the mean of its divisors is an integer number (61711700152566).
Almost surely, 2123423400305131 is an apocalyptic number.
123423400305131 is a deficient number, since it is larger than the sum of its proper divisors (1).
123423400305131 is an equidigital number, since it uses as much as digits as its factorization.
123423400305131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 25920, while the sum is 32.
Adding to 123423400305131 its reverse (131503004324321), we get a palindrome (254926404629452).
The spelling of 123423400305131 in words is "one hundred twenty-three trillion, four hundred twenty-three billion, four hundred million, three hundred five thousand, one hundred thirty-one".
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