Search a number
-
+
12343424242441 is a prime number
BaseRepresentation
bin1011001110011110110101…
…1010101101001100001001
31121201000112110101012121011
42303213231122231030021
53104213313101224231
642130254003243521
72412532362631645
oct263475532551411
947630473335534
1012343424242441
113a298a9213176
1214742a39795a1
136b6c97b33cb6
143095d3da9c25
15166132a0b9b1
hexb39ed6ad309

12343424242441 has 2 divisors, whose sum is σ = 12343424242442. Its totient is φ = 12343424242440.

The previous prime is 12343424242397. The next prime is 12343424242447. The reversal of 12343424242441 is 14424242434321.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6354538514041 + 5988885728400 = 2520821^2 + 2447220^2 .

It is a cyclic number.

It is not a de Polignac number, because 12343424242441 - 215 = 12343424209673 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12343424242394 and 12343424242403.

It is not a weakly prime, because it can be changed into another prime (12343424242447) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6171712121220 + 6171712121221.

It is an arithmetic number, because the mean of its divisors is an integer number (6171712121221).

Almost surely, 212343424242441 is an apocalyptic number.

It is an amenable number.

12343424242441 is a deficient number, since it is larger than the sum of its proper divisors (1).

12343424242441 is an equidigital number, since it uses as much as digits as its factorization.

12343424242441 is an evil number, because the sum of its binary digits is even.

The product of its digits is 589824, while the sum is 40.

Adding to 12343424242441 its reverse (14424242434321), we get a palindrome (26767666676762).

The spelling of 12343424242441 in words is "twelve trillion, three hundred forty-three billion, four hundred twenty-four million, two hundred forty-two thousand, four hundred forty-one".