Base | Representation |
---|---|
bin | 111001011111000110… |
… | …0111011000110111001 |
3 | 102210122110020001011111 |
4 | 1302332030323012321 |
5 | 4010311214040121 |
6 | 132413501000321 |
7 | 11630131621552 |
oct | 1627614730671 |
9 | 383573201144 |
10 | 123450143161 |
11 | 4839a429804 |
12 | 1bb132530a1 |
13 | b844c187b7 |
14 | 5d91647329 |
15 | 3327d152e1 |
hex | 1cbe33b1b9 |
123450143161 has 2 divisors, whose sum is σ = 123450143162. Its totient is φ = 123450143160.
The previous prime is 123450143119. The next prime is 123450143197. The reversal of 123450143161 is 161341054321.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 122206875561 + 1243267600 = 349581^2 + 35260^2 .
It is an emirp because it is prime and its reverse (161341054321) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 123450143161 - 221 = 123448046009 is a prime.
It is not a weakly prime, because it can be changed into another prime (123450143101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61725071580 + 61725071581.
It is an arithmetic number, because the mean of its divisors is an integer number (61725071581).
Almost surely, 2123450143161 is an apocalyptic number.
It is an amenable number.
123450143161 is a deficient number, since it is larger than the sum of its proper divisors (1).
123450143161 is an equidigital number, since it uses as much as digits as its factorization.
123450143161 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8640, while the sum is 31.
Adding to 123450143161 its reverse (161341054321), we get a palindrome (284791197482).
The spelling of 123450143161 in words is "one hundred twenty-three billion, four hundred fifty million, one hundred forty-three thousand, one hundred sixty-one".
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