Search a number
-
+
123455134203 = 341151711401
BaseRepresentation
bin111001011111001111…
…1111101100111111011
3102210122210121121120220
41302332133331213323
54010314003243303
6132414155551123
711630222216652
oct1627637754773
9383583547526
10123455134203
11483a2228635
121bb14a5b4a3
13b845c7548b
145d92186199
15332849e053
hex1cbe7fd9fb

123455134203 has 4 divisors (see below), whose sum is σ = 164606845608. Its totient is φ = 82303422800.

The previous prime is 123455134193. The next prime is 123455134211. The reversal of 123455134203 is 302431554321.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 123455134203 - 220 = 123454085627 is a prime.

It is a super-2 number, since 2×1234551342032 (a number of 23 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (123455134273) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20575855698 + ... + 20575855703.

It is an arithmetic number, because the mean of its divisors is an integer number (41151711402).

Almost surely, 2123455134203 is an apocalyptic number.

123455134203 is a deficient number, since it is larger than the sum of its proper divisors (41151711405).

123455134203 is an equidigital number, since it uses as much as digits as its factorization.

123455134203 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 41151711404.

The product of its (nonzero) digits is 43200, while the sum is 33.

Adding to 123455134203 its reverse (302431554321), we get a palindrome (425886688524).

The spelling of 123455134203 in words is "one hundred twenty-three billion, four hundred fifty-five million, one hundred thirty-four thousand, two hundred three".

Divisors: 1 3 41151711401 123455134203