Base | Representation |
---|---|
bin | 111001011111100011… |
… | …1001011010111100001 |
3 | 102210200111221212222022 |
4 | 1302333013023113201 |
5 | 4010324121222423 |
6 | 132415204151225 |
7 | 11630405463356 |
oct | 1627707132741 |
9 | 383614855868 |
10 | 123465414113 |
11 | 483a800a028 |
12 | 1bb18398515 |
13 | b848134572 |
14 | 5d936a062d |
15 | 332932edc8 |
hex | 1cbf1cb5e1 |
123465414113 has 2 divisors, whose sum is σ = 123465414114. Its totient is φ = 123465414112.
The previous prime is 123465414101. The next prime is 123465414133. The reversal of 123465414113 is 311414564321.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 111791259904 + 11674154209 = 334352^2 + 108047^2 .
It is a cyclic number.
It is not a de Polignac number, because 123465414113 - 26 = 123465414049 is a prime.
It is not a weakly prime, because it can be changed into another prime (123465414133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61732707056 + 61732707057.
It is an arithmetic number, because the mean of its divisors is an integer number (61732707057).
Almost surely, 2123465414113 is an apocalyptic number.
It is an amenable number.
123465414113 is a deficient number, since it is larger than the sum of its proper divisors (1).
123465414113 is an equidigital number, since it uses as much as digits as its factorization.
123465414113 is an evil number, because the sum of its binary digits is even.
The product of its digits is 34560, while the sum is 35.
Adding to 123465414113 its reverse (311414564321), we get a palindrome (434879978434).
The spelling of 123465414113 in words is "one hundred twenty-three billion, four hundred sixty-five million, four hundred fourteen thousand, one hundred thirteen".
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