12351403340433 has 48 divisors (see below), whose sum is σ = 18789583904000. Its totient is φ = 8106738007680.

The previous prime is 12351403340417. The next prime is 12351403340447. The reversal of 12351403340433 is 33404330415321.

12351403340433 is a `hidden beast` number, since 1 + 235 + 1 + 40 + 3 + 340 + 43 + 3 = 666.

It is not a de Polignac number, because 12351403340433 - 2⁴ = 12351403340417 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12351403345433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 5777973 + ... + 7621533.

Almost surely, 2^{12351403340433} is an apocalyptic number.

It is an amenable number.

12351403340433 is a deficient number, since it is larger than the sum of its proper divisors (6438180563567).

12351403340433 is an equidigital number, since it uses as much as digits as its factorization.

12351403340433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1844004 (or 1843992 counting only the distinct ones).

The product of its (nonzero) digits is 155520, while the sum is 36.

Adding to 12351403340433 its reverse (33404330415321), we get a palindrome (45755733755754).

The spelling of 12351403340433 in words is "twelve trillion, three hundred fifty-one billion, four hundred three million, three hundred forty thousand, four hundred thirty-three".