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1235143100153 = 19199326671013
BaseRepresentation
bin10001111110010100010…
…001000000011011111001
311101002010020122120102102
4101332110101000123321
5130214033113201103
62343230015113145
7155143666060664
oct21762421003371
94332106576372
101235143100153
11436904097416
1217b466b127b5
138c620362b21
1443ad1a446db
15221e00d5e88
hex11f944406f9

1235143100153 has 8 divisors (see below), whose sum is σ = 1306684056000. Its totient is φ = 1164255486768.

The previous prime is 1235143100131. The next prime is 1235143100189. The reversal of 1235143100153 is 3510013415321.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1235143100153 - 228 = 1234874664697 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1235143120153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 163331726 + ... + 163339287.

It is an arithmetic number, because the mean of its divisors is an integer number (163335507000).

Almost surely, 21235143100153 is an apocalyptic number.

It is an amenable number.

1235143100153 is a deficient number, since it is larger than the sum of its proper divisors (71540955847).

1235143100153 is a wasteful number, since it uses less digits than its factorization.

1235143100153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 326671231.

The product of its (nonzero) digits is 5400, while the sum is 29.

Adding to 1235143100153 its reverse (3510013415321), we get a palindrome (4745156515474).

The spelling of 1235143100153 in words is "one trillion, two hundred thirty-five billion, one hundred forty-three million, one hundred thousand, one hundred fifty-three".

Divisors: 1 19 199 3781 326671013 6206749247 65007531587 1235143100153