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12354363514147 is a prime number
BaseRepresentation
bin1011001111000111100101…
…1100101101110100100011
31121202001202211112210021111
42303301321130231310203
53104403214024423042
642135303302004151
72413400434125244
oct263617134556443
947661684483244
1012354363514147
113a33502142996
121476437416657
136b801c2b8035
14309d50b8cccb
151665730a2517
hexb3c7972dd23

12354363514147 has 2 divisors, whose sum is σ = 12354363514148. Its totient is φ = 12354363514146.

The previous prime is 12354363514121. The next prime is 12354363514223. The reversal of 12354363514147 is 74141536345321.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12354363514147 is a prime.

It is a super-2 number, since 2×123543635141472 (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 12354363514147.

It is not a weakly prime, because it can be changed into another prime (12354363514547) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6177181757073 + 6177181757074.

It is an arithmetic number, because the mean of its divisors is an integer number (6177181757074).

Almost surely, 212354363514147 is an apocalyptic number.

12354363514147 is a deficient number, since it is larger than the sum of its proper divisors (1).

12354363514147 is an equidigital number, since it uses as much as digits as its factorization.

12354363514147 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 3628800, while the sum is 49.

Adding to 12354363514147 its reverse (74141536345321), we get a palindrome (86495899859468).

The spelling of 12354363514147 in words is "twelve trillion, three hundred fifty-four billion, three hundred sixty-three million, five hundred fourteen thousand, one hundred forty-seven".