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123545242020433 is a prime number
BaseRepresentation
bin11100000101110100011110…
…010000111010101001010001
3121012102210212100002210022111
4130011310132100322221101
5112143131123424123213
61114431522313105321
735010564161145052
oct3405643620725121
9535383770083274
10123545242020433
1136402274336a12
1211a33a8b6b8241
1353c236019611c
14227189ba18729
15e43a667c5a3d
hex705d1e43aa51

123545242020433 has 2 divisors, whose sum is σ = 123545242020434. Its totient is φ = 123545242020432.

The previous prime is 123545242020377. The next prime is 123545242020491. The reversal of 123545242020433 is 334020242545321.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 68806892280064 + 54738349740369 = 8294992^2 + 7398537^2 .

It is an emirp because it is prime and its reverse (334020242545321) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-123545242020433 is a prime.

It is not a weakly prime, because it can be changed into another prime (123545242020833) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61772621010216 + 61772621010217.

It is an arithmetic number, because the mean of its divisors is an integer number (61772621010217).

Almost surely, 2123545242020433 is an apocalyptic number.

It is an amenable number.

123545242020433 is a deficient number, since it is larger than the sum of its proper divisors (1).

123545242020433 is an equidigital number, since it uses as much as digits as its factorization.

123545242020433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 691200, while the sum is 40.

Adding to 123545242020433 its reverse (334020242545321), we get a palindrome (457565484565754).

The spelling of 123545242020433 in words is "one hundred twenty-three trillion, five hundred forty-five billion, two hundred forty-two million, twenty thousand, four hundred thirty-three".