12383411341138 has 4 divisors (see below), whose sum is σ = 18575117011710. Its totient is φ = 6191705670568.

The previous prime is 12383411341109. The next prime is 12383411341139. The reversal of 12383411341138 is 83114311438321.

12383411341138 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 10294684012089 + 2088727329049 = 3208533^2 + 1445243^2 .

It is a super-2 number, since 2×12383411341138² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12383411341094 and 12383411341103.

It is not an unprimeable number, because it can be changed into a prime (12383411341139) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3095852835283 + ... + 3095852835286.

Almost surely, 2^{12383411341138} is an apocalyptic number.

12383411341138 is a deficient number, since it is larger than the sum of its proper divisors (6191705670572).

12383411341138 is an equidigital number, since it uses as much as digits as its factorization.

12383411341138 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6191705670571.

The product of its digits is 165888, while the sum is 43.

Adding to 12383411341138 its reverse (83114311438321), we get a palindrome (95497722779459).

The spelling of 12383411341138 in words is "twelve trillion, three hundred eighty-three billion, four hundred eleven million, three hundred forty-one thousand, one hundred thirty-eight".