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12383868134969 is a prime number
BaseRepresentation
bin1011010000110101100000…
…0011111010011000111001
31121211212221001200211011122
42310031120003322120321
53110344130220304334
642201023120235025
72415463540224032
oct264153003723071
947755831624148
1012383868134969
113a44a72796241
1214800b046ba75
136baa41b55356
1430b54d4c5a89
151671ed47732e
hexb43580fa639

12383868134969 has 2 divisors, whose sum is σ = 12383868134970. Its totient is φ = 12383868134968.

The previous prime is 12383868134933. The next prime is 12383868135053. The reversal of 12383868134969 is 96943186838321.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6245425837225 + 6138442297744 = 2499085^2 + 2477588^2 .

It is an emirp because it is prime and its reverse (96943186838321) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12383868134969 - 28 = 12383868134713 is a prime.

It is a super-2 number, since 2×123838681349692 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (12383868134669) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6191934067484 + 6191934067485.

It is an arithmetic number, because the mean of its divisors is an integer number (6191934067485).

Almost surely, 212383868134969 is an apocalyptic number.

It is an amenable number.

12383868134969 is a deficient number, since it is larger than the sum of its proper divisors (1).

12383868134969 is an equidigital number, since it uses as much as digits as its factorization.

12383868134969 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 322486272, while the sum is 71.

The spelling of 12383868134969 in words is "twelve trillion, three hundred eighty-three billion, eight hundred sixty-eight million, one hundred thirty-four thousand, nine hundred sixty-nine".