Base | Representation |
---|---|
bin | 10010000001100101111… |
… | …010101101011011010011 |
3 | 11101102012101012111102121 |
4 | 102001211322231123103 |
5 | 130243234040023413 |
6 | 2345011024355111 |
7 | 155330106164662 |
oct | 22014572553323 |
9 | 4342171174377 |
10 | 1238660470483 |
11 | 4383495a8847 |
12 | 180088a75a97 |
13 | 8ca60ca1947 |
14 | 43d46c44dd9 |
15 | 22348cc4b8d |
hex | 12065ead6d3 |
1238660470483 has 2 divisors, whose sum is σ = 1238660470484. Its totient is φ = 1238660470482.
The previous prime is 1238660470451. The next prime is 1238660470513. The reversal of 1238660470483 is 3840740668321.
It is a strong prime.
It is an emirp because it is prime and its reverse (3840740668321) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1238660470483 - 25 = 1238660470451 is a prime.
It is a super-2 number, since 2×12386604704832 (a number of 25 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 1238660470483.
It is not a weakly prime, because it can be changed into another prime (1238660470283) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 619330235241 + 619330235242.
It is an arithmetic number, because the mean of its divisors is an integer number (619330235242).
Almost surely, 21238660470483 is an apocalyptic number.
1238660470483 is a deficient number, since it is larger than the sum of its proper divisors (1).
1238660470483 is an equidigital number, since it uses as much as digits as its factorization.
1238660470483 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4644864, while the sum is 52.
The spelling of 1238660470483 in words is "one trillion, two hundred thirty-eight billion, six hundred sixty million, four hundred seventy thousand, four hundred eighty-three".
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