Base | Representation |
---|---|
bin | 10111000110001100… |
… | …11001100101111010 |
3 | 1012000011212022111101 |
4 | 23203012121211322 |
5 | 200343402242224 |
6 | 5410235522014 |
7 | 616166414014 |
oct | 134306314572 |
9 | 35004768441 |
10 | 12400040314 |
11 | 5293554902 |
12 | 24a08b930a |
13 | 1227cbb57c |
14 | 858bd31b4 |
15 | 4c8941044 |
hex | 2e319997a |
12400040314 has 4 divisors (see below), whose sum is σ = 18600060474. Its totient is φ = 6200020156.
The previous prime is 12400040267. The next prime is 12400040339. The reversal of 12400040314 is 41304000421.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 9406090225 + 2993950089 = 96985^2 + 54717^2 .
It is a junction number, because it is equal to n+sod(n) for n = 12400040291 and 12400040300.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3100010077 + ... + 3100010080.
Almost surely, 212400040314 is an apocalyptic number.
12400040314 is a deficient number, since it is larger than the sum of its proper divisors (6200020160).
12400040314 is an equidigital number, since it uses as much as digits as its factorization.
12400040314 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6200020159.
The product of its (nonzero) digits is 384, while the sum is 19.
Adding to 12400040314 its reverse (41304000421), we get a palindrome (53704040735).
The spelling of 12400040314 in words is "twelve billion, four hundred million, forty thousand, three hundred fourteen".
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