Base | Representation |
---|---|
bin | 11100001100011100011001… |
… | …001010101001011000011011 |
3 | 121021001022202200110120220220 |
4 | 130030130121022221120123 |
5 | 112223110331243233110 |
6 | 1115421001413451123 |
7 | 35055510035634666 |
oct | 3414343112513033 |
9 | 537038680416826 |
10 | 124000423024155 |
11 | 36568314127117 |
12 | 11aa8142940aa3 |
13 | 5426260a68752 |
14 | 228991c6486dd |
15 | e50807821370 |
hex | 70c7192a961b |
124000423024155 has 16 divisors (see below), whose sum is σ = 198400816610304. Its totient is φ = 66133512355680.
The previous prime is 124000423024151. The next prime is 124000423024193. The reversal of 124000423024155 is 551420324000421.
It is not a de Polignac number, because 124000423024155 - 22 = 124000423024151 is a prime.
It is a super-2 number, since 2×1240004230241552 (a number of 29 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (124000423024151) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 35077212 + ... + 38450118.
It is an arithmetic number, because the mean of its divisors is an integer number (12400051038144).
Almost surely, 2124000423024155 is an apocalyptic number.
124000423024155 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
124000423024155 is a deficient number, since it is larger than the sum of its proper divisors (74400393586149).
124000423024155 is a wasteful number, since it uses less digits than its factorization.
124000423024155 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5823826.
The product of its (nonzero) digits is 38400, while the sum is 33.
Adding to 124000423024155 its reverse (551420324000421), we get a palindrome (675420747024576).
The spelling of 124000423024155 in words is "one hundred twenty-four trillion, four hundred twenty-three million, twenty-four thousand, one hundred fifty-five".
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