Base | Representation |
---|---|
bin | 10010000010111011110… |
… | …110010010001101110111 |
3 | 11101112220211222110100110 |
4 | 102002323312102031313 |
5 | 130304212122313111 |
6 | 2345410044514103 |
7 | 155410613235162 |
oct | 22027366221567 |
9 | 4345824873313 |
10 | 1240102151031 |
11 | 438a19375777 |
12 | 18040b84b933 |
13 | 8cc30884b63 |
14 | 440424c6ad9 |
15 | 223d064e5a6 |
hex | 120bbd92377 |
1240102151031 has 16 divisors (see below), whose sum is σ = 1717642598400. Its totient is φ = 794886798048.
The previous prime is 1240102151017. The next prime is 1240102151033. The reversal of 1240102151031 is 1301512010421.
It is not a de Polignac number, because 1240102151031 - 29 = 1240102150519 is a prime.
It is a super-2 number, since 2×12401021510312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1240102150989 and 1240102151007.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1240102151033) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 29799391 + ... + 29840976.
It is an arithmetic number, because the mean of its divisors is an integer number (107352662400).
Almost surely, 21240102151031 is an apocalyptic number.
1240102151031 is a deficient number, since it is larger than the sum of its proper divisors (477540447369).
1240102151031 is a wasteful number, since it uses less digits than its factorization.
1240102151031 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 59640638.
The product of its (nonzero) digits is 240, while the sum is 21.
Adding to 1240102151031 its reverse (1301512010421), we get a palindrome (2541614161452).
The spelling of 1240102151031 in words is "one trillion, two hundred forty billion, one hundred two million, one hundred fifty-one thousand, thirty-one".
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