Base | Representation |
---|---|
bin | 10010000010111011111… |
… | …010011010011001101100 |
3 | 11101112220221000102201021 |
4 | 102002323322122121230 |
5 | 130304212411430012 |
6 | 2345410124023524 |
7 | 155410625363041 |
oct | 22027372323154 |
9 | 4345827012637 |
10 | 1240103233132 |
11 | 438a19a44775 |
12 | 180410091ba4 |
13 | 8cc30b7355a |
14 | 440426c91c8 |
15 | 223d07b5007 |
hex | 120bbe9a66c |
1240103233132 has 12 divisors (see below), whose sum is σ = 2170237108480. Its totient is φ = 620035487856.
The previous prime is 1240103233099. The next prime is 1240103233151. The reversal of 1240103233132 is 2313323010421.
It is a junction number, because it is equal to n+sod(n) for n = 1240103233097 and 1240103233106.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3858348 + ... + 4167379.
Almost surely, 21240103233132 is an apocalyptic number.
It is an amenable number.
1240103233132 is a deficient number, since it is larger than the sum of its proper divisors (930133875348).
1240103233132 is a wasteful number, since it uses less digits than its factorization.
1240103233132 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8064360 (or 8064358 counting only the distinct ones).
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 1240103233132 its reverse (2313323010421), we get a palindrome (3553426243553).
The spelling of 1240103233132 in words is "one trillion, two hundred forty billion, one hundred three million, two hundred thirty-three thousand, one hundred thirty-two".
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