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124012532113 is a prime number
BaseRepresentation
bin111001101111110111…
…0010001000110010001
3102212002122110100202221
41303133232101012101
54012434202011423
6132545350541041
711650101062521
oct1633756210621
9385078410687
10124012532113
1148658928968
122004b667781
13b9045a6022
1460061dd681
15335c3a3e5d
hex1cdfb91191

124012532113 has 2 divisors, whose sum is σ = 124012532114. Its totient is φ = 124012532112.

The previous prime is 124012532099. The next prime is 124012532117. The reversal of 124012532113 is 311235210421.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 81548511489 + 42464020624 = 285567^2 + 206068^2 .

It is an emirp because it is prime and its reverse (311235210421) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 124012532113 - 25 = 124012532081 is a prime.

It is not a weakly prime, because it can be changed into another prime (124012532117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62006266056 + 62006266057.

It is an arithmetic number, because the mean of its divisors is an integer number (62006266057).

Almost surely, 2124012532113 is an apocalyptic number.

It is an amenable number.

124012532113 is a deficient number, since it is larger than the sum of its proper divisors (1).

124012532113 is an equidigital number, since it uses as much as digits as its factorization.

124012532113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 124012532113 its reverse (311235210421), we get a palindrome (435247742534).

The spelling of 124012532113 in words is "one hundred twenty-four billion, twelve million, five hundred thirty-two thousand, one hundred thirteen".