Base | Representation |
---|---|
bin | 10111000110010110… |
… | …10000001100110011 |
3 | 1012000021020221200201 |
4 | 23203023100030303 |
5 | 200344214000223 |
6 | 5410323100031 |
7 | 616213263133 |
oct | 134313201463 |
9 | 35007227621 |
10 | 12401312563 |
11 | 5294243752 |
12 | 24a1211617 |
13 | 1228345693 |
14 | 859044ac3 |
15 | 4c8ae2ead |
hex | 2e32d0333 |
12401312563 has 2 divisors, whose sum is σ = 12401312564. Its totient is φ = 12401312562.
The previous prime is 12401312527. The next prime is 12401312587. The reversal of 12401312563 is 36521310421.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12401312563 - 229 = 11864441651 is a prime.
It is not a weakly prime, because it can be changed into another prime (12401312513) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6200656281 + 6200656282.
It is an arithmetic number, because the mean of its divisors is an integer number (6200656282).
Almost surely, 212401312563 is an apocalyptic number.
12401312563 is a deficient number, since it is larger than the sum of its proper divisors (1).
12401312563 is an equidigital number, since it uses as much as digits as its factorization.
12401312563 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4320, while the sum is 28.
Adding to 12401312563 its reverse (36521310421), we get a palindrome (48922622984).
The spelling of 12401312563 in words is "twelve billion, four hundred one million, three hundred twelve thousand, five hundred sixty-three".
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