Base | Representation |
---|---|
bin | 1011010001110110100100… |
… | …1000101001000101110011 |
3 | 1121220120000022122220020011 |
4 | 2310131221020221011303 |
5 | 3111140413110103231 |
6 | 42213032220155351 |
7 | 2416652425423555 |
oct | 264355110510563 |
9 | 47816008586204 |
10 | 12401334456691 |
11 | 3a51415aa9274 |
12 | 1483565998b57 |
13 | 6bc59663b56b |
14 | 30c3290b14d5 |
15 | 1678c1a639b1 |
hex | b4769229173 |
12401334456691 has 2 divisors, whose sum is σ = 12401334456692. Its totient is φ = 12401334456690.
The previous prime is 12401334456523. The next prime is 12401334456739. The reversal of 12401334456691 is 19665443310421.
It is a strong prime.
It is an emirp because it is prime and its reverse (19665443310421) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12401334456691 - 213 = 12401334448499 is a prime.
It is a super-2 number, since 2×124013344566912 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (12401334436691) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6200667228345 + 6200667228346.
It is an arithmetic number, because the mean of its divisors is an integer number (6200667228346).
Almost surely, 212401334456691 is an apocalyptic number.
12401334456691 is a deficient number, since it is larger than the sum of its proper divisors (1).
12401334456691 is an equidigital number, since it uses as much as digits as its factorization.
12401334456691 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1866240, while the sum is 49.
The spelling of 12401334456691 in words is "twelve trillion, four hundred one billion, three hundred thirty-four million, four hundred fifty-six thousand, six hundred ninety-one".
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