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1240142221003 = 7177163174429
BaseRepresentation
bin10010000010111110001…
…111001000111011001011
311101120000122101020000111
4102002332033020323023
5130304302402033003
62345414035415151
7155411610644230
oct22027617107313
94346018336014
101240142221003
11438a39a53954
121804211544b7
138cc38c744ba
1444047957787
15223d3e16e6d
hex120be3c8ecb

1240142221003 has 4 divisors (see below), whose sum is σ = 1417305395440. Its totient is φ = 1062979046568.

The previous prime is 1240142220991. The next prime is 1240142221079. The reversal of 1240142221003 is 3001222410421.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1240142221003 - 29 = 1240142220491 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1240142221403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 88581587208 + ... + 88581587221.

It is an arithmetic number, because the mean of its divisors is an integer number (354326348860).

Almost surely, 21240142221003 is an apocalyptic number.

1240142221003 is a deficient number, since it is larger than the sum of its proper divisors (177163174437).

1240142221003 is an equidigital number, since it uses as much as digits as its factorization.

1240142221003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 177163174436.

The product of its (nonzero) digits is 768, while the sum is 22.

Adding to 1240142221003 its reverse (3001222410421), we get a palindrome (4241364631424).

The spelling of 1240142221003 in words is "one trillion, two hundred forty billion, one hundred forty-two million, two hundred twenty-one thousand, three".

Divisors: 1 7 177163174429 1240142221003