12401430434131 has 4 divisors (see below), whose sum is σ = 12403093054600. Its totient is φ = 12399767813664.

The previous prime is 12401430434051. The next prime is 12401430434167. The reversal of 12401430434131 is 13143403410421.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12401430434131 - 2⁹ = 12401430433619 is a prime.

It is a super-2 number, since 2×12401430434131² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12401430434093 and 12401430434102.

It is not an unprimeable number, because it can be changed into a prime (12401430434171) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 831299046 + ... + 831313963.

It is an arithmetic number, because the mean of its divisors is an integer number (3100773263650).

Almost surely, 2^{12401430434131} is an apocalyptic number.

12401430434131 is a deficient number, since it is larger than the sum of its proper divisors (1662620469).

12401430434131 is an equidigital number, since it uses as much as digits as its factorization.

12401430434131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1662620468.

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 12401430434131 its reverse (13143403410421), we get a palindrome (25544833844552).

The spelling of 12401430434131 in words is "twelve trillion, four hundred one billion, four hundred thirty million, four hundred thirty-four thousand, one hundred thirty-one".