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12401601433297 is a prime number
BaseRepresentation
bin1011010001110111100100…
…0011000100111011010001
31121220120200221000201021121
42310131321003010323101
53111141434431331142
642213114514322241
72416662146613166
oct264357103047321
947816627021247
1012401601433297
113a5154277779a
12148361b289381
136bc609a4619b
1430c35272a06d
151678da1ecc67
hexb47790c4ed1

12401601433297 has 2 divisors, whose sum is σ = 12401601433298. Its totient is φ = 12401601433296.

The previous prime is 12401601433229. The next prime is 12401601433357. The reversal of 12401601433297 is 79233410610421.

12401601433297 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12267814471936 + 133786961361 = 3502544^2 + 365769^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12401601433297 is a prime.

It is a super-2 number, since 2×124016014332972 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (12401601403297) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6200800716648 + 6200800716649.

It is an arithmetic number, because the mean of its divisors is an integer number (6200800716649).

Almost surely, 212401601433297 is an apocalyptic number.

It is an amenable number.

12401601433297 is a deficient number, since it is larger than the sum of its proper divisors (1).

12401601433297 is an equidigital number, since it uses as much as digits as its factorization.

12401601433297 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 217728, while the sum is 43.

The spelling of 12401601433297 in words is "twelve trillion, four hundred one billion, six hundred one million, four hundred thirty-three thousand, two hundred ninety-seven".