Base | Representation |
---|---|
bin | 10010000011000001111… |
… | …100110110010100000001 |
3 | 11101120011222122002210211 |
4 | 102003001330312110001 |
5 | 130304414330110131 |
6 | 2345424143154121 |
7 | 155413265416633 |
oct | 22030174662401 |
9 | 4346158562724 |
10 | 1240204535041 |
11 | 438a7114535a |
12 | 180439ba5941 |
13 | 8cc48b51804 |
14 | 44051d38a53 |
15 | 223d96255b1 |
hex | 120c1f36501 |
1240204535041 has 2 divisors, whose sum is σ = 1240204535042. Its totient is φ = 1240204535040.
The previous prime is 1240204535029. The next prime is 1240204535111. The reversal of 1240204535041 is 1405354020421.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1239971331600 + 233203441 = 1113540^2 + 15271^2 .
It is a cyclic number.
It is not a de Polignac number, because 1240204535041 - 221 = 1240202437889 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1240204534994 and 1240204535012.
It is not a weakly prime, because it can be changed into another prime (1240204535441) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 620102267520 + 620102267521.
It is an arithmetic number, because the mean of its divisors is an integer number (620102267521).
Almost surely, 21240204535041 is an apocalyptic number.
It is an amenable number.
1240204535041 is a deficient number, since it is larger than the sum of its proper divisors (1).
1240204535041 is an equidigital number, since it uses as much as digits as its factorization.
1240204535041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 19200, while the sum is 31.
Adding to 1240204535041 its reverse (1405354020421), we get a palindrome (2645558555462).
The spelling of 1240204535041 in words is "one trillion, two hundred forty billion, two hundred four million, five hundred thirty-five thousand, forty-one".
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