Base | Representation |
---|---|
bin | 1011010001111001110101… |
… | …1001001100011101111011 |
3 | 1121220122021102102122012211 |
4 | 2310132131121030131323 |
5 | 3111144212032224011 |
6 | 42213255220115551 |
7 | 2420013232625140 |
oct | 264363531143573 |
9 | 47818242378184 |
10 | 12402211211131 |
11 | 3a518259a3915 |
12 | 148376b535bb7 |
13 | 6bc6a6186481 |
14 | 30c3ad6da3c7 |
15 | 1679239ecb21 |
hex | b479d64c77b |
12402211211131 has 16 divisors (see below), whose sum is σ = 14802738306048. Its totient is φ = 10159662506400.
The previous prime is 12402211211083. The next prime is 12402211211141. The reversal of 12402211211131 is 13111211220421.
It is not a de Polignac number, because 12402211211131 - 211 = 12402211209083 is a prime.
It is a super-2 number, since 2×124022112111312 (a number of 27 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (12402211211141) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 32423055 + ... + 32803336.
It is an arithmetic number, because the mean of its divisors is an integer number (925171144128).
Almost surely, 212402211211131 is an apocalyptic number.
12402211211131 is a deficient number, since it is larger than the sum of its proper divisors (2400527094917).
12402211211131 is a wasteful number, since it uses less digits than its factorization.
12402211211131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 65227602.
The product of its (nonzero) digits is 192, while the sum is 22.
Adding to 12402211211131 its reverse (13111211220421), we get a palindrome (25513422431552).
The spelling of 12402211211131 in words is "twelve trillion, four hundred two billion, two hundred eleven million, two hundred eleven thousand, one hundred thirty-one".
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