Base | Representation |
---|---|
bin | 10111000110011101… |
… | …01100000010001001 |
3 | 1012000022221200212021 |
4 | 23203032230002021 |
5 | 200344431304001 |
6 | 5410354244441 |
7 | 616224033253 |
oct | 134316540211 |
9 | 35008850767 |
10 | 12402213001 |
11 | 52947a9212 |
12 | 24a1586721 |
13 | 122859c499 |
14 | 8591dacd3 |
15 | 4c8c1eba1 |
hex | 2e33ac089 |
12402213001 has 4 divisors (see below), whose sum is σ = 12405383172. Its totient is φ = 12399042832.
The previous prime is 12402212983. The next prime is 12402213013. The reversal of 12402213001 is 10031220421.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 10370367225 + 2031845776 = 101835^2 + 45076^2 .
It is a cyclic number.
It is not a de Polignac number, because 12402213001 - 29 = 12402212489 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12402213091) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1579210 + ... + 1587043.
It is an arithmetic number, because the mean of its divisors is an integer number (3101345793).
Almost surely, 212402213001 is an apocalyptic number.
It is an amenable number.
12402213001 is a deficient number, since it is larger than the sum of its proper divisors (3170171).
12402213001 is an equidigital number, since it uses as much as digits as its factorization.
12402213001 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3170170.
The product of its (nonzero) digits is 96, while the sum is 16.
Adding to 12402213001 its reverse (10031220421), we get a palindrome (22433433422).
The spelling of 12402213001 in words is "twelve billion, four hundred two million, two hundred thirteen thousand, one".
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