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12402412014457 = 93581913253003
BaseRepresentation
bin1011010001111010100101…
…0111001100101101111001
31121220122210102021111121001
42310132221113030231321
53111200114433430312
642213331152045001
72420021221466443
oct264365127145571
947818712244531
1012402412014457
113a51919285383
121483806833761
136bc7089622ca
1430c3cc24b493
15167936465057
hexb47a95ccb79

12402412014457 has 4 divisors (see below), whose sum is σ = 12402426203280. Its totient is φ = 12402397825636.

The previous prime is 12402412014449. The next prime is 12402412014497. The reversal of 12402412014457 is 75441021420421.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12402412014457 - 23 = 12402412014449 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12402412014407) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5690683 + ... + 7562320.

It is an arithmetic number, because the mean of its divisors is an integer number (3100606550820).

Almost surely, 212402412014457 is an apocalyptic number.

It is an amenable number.

12402412014457 is a deficient number, since it is larger than the sum of its proper divisors (14188823).

12402412014457 is an equidigital number, since it uses as much as digits as its factorization.

12402412014457 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 14188822.

The product of its (nonzero) digits is 71680, while the sum is 37.

Adding to 12402412014457 its reverse (75441021420421), we get a palindrome (87843433434878).

The spelling of 12402412014457 in words is "twelve trillion, four hundred two billion, four hundred twelve million, fourteen thousand, four hundred fifty-seven".

Divisors: 1 935819 13253003 12402412014457