Base | Representation |
---|---|
bin | 10111000110011111… |
… | …00011110001100001 |
3 | 1012000100101022001021 |
4 | 23203033203301201 |
5 | 200400011110223 |
6 | 5410403205441 |
7 | 616226004013 |
oct | 134317436141 |
9 | 35010338037 |
10 | 12402441313 |
11 | 52949447a9 |
12 | 24a1676881 |
13 | 122864c392 |
14 | 85925a1b3 |
15 | 4c8c6765d |
hex | 2e33e3c61 |
12402441313 has 2 divisors, whose sum is σ = 12402441314. Its totient is φ = 12402441312.
The previous prime is 12402441301. The next prime is 12402441377. The reversal of 12402441313 is 31314420421.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9699689169 + 2702752144 = 98487^2 + 51988^2 .
It is an emirp because it is prime and its reverse (31314420421) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12402441313 - 217 = 12402310241 is a prime.
It is not a weakly prime, because it can be changed into another prime (12402441713) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6201220656 + 6201220657.
It is an arithmetic number, because the mean of its divisors is an integer number (6201220657).
Almost surely, 212402441313 is an apocalyptic number.
It is an amenable number.
12402441313 is a deficient number, since it is larger than the sum of its proper divisors (1).
12402441313 is an equidigital number, since it uses as much as digits as its factorization.
12402441313 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 12402441313 its reverse (31314420421), we get a palindrome (43716861734).
The spelling of 12402441313 in words is "twelve billion, four hundred two million, four hundred forty-one thousand, three hundred thirteen".
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