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12403117451 = 14983242399
BaseRepresentation
bin10111000110100100…
…01000110110001011
31012000101122122112102
423203102020312023
5200400144224301
65410425504015
7616234521164
oct134322106613
935011578472
1012403117451
11529526679a
1224a194200b
13122882806a
1485939476b
154c8d4cb6b
hex2e3488d8b

12403117451 has 4 divisors (see below), whose sum is σ = 12486360000. Its totient is φ = 12319874904.

The previous prime is 12403117403. The next prime is 12403117457. The reversal of 12403117451 is 15471130421.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 15471130421 = 23557656753.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12403117451 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12403117457) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 41621051 + ... + 41621348.

It is an arithmetic number, because the mean of its divisors is an integer number (3121590000).

Almost surely, 212403117451 is an apocalyptic number.

12403117451 is a deficient number, since it is larger than the sum of its proper divisors (83242549).

12403117451 is an equidigital number, since it uses as much as digits as its factorization.

12403117451 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 83242548.

The product of its (nonzero) digits is 3360, while the sum is 29.

Adding to 12403117451 its reverse (15471130421), we get a palindrome (27874247872).

The spelling of 12403117451 in words is "twelve billion, four hundred three million, one hundred seventeen thousand, four hundred fifty-one".

Divisors: 1 149 83242399 12403117451