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1240342113 = 31373301127
BaseRepresentation
bin100100111101110…
…0001111001100001
310012102220220111210
41021323201321201
510020011421423
6323024500333
742510506523
oct11173417141
93172826453
101240342113
1158716042a
122a747a6a9
13169c7a95a
14baa31a13
1573d58b93
hex49ee1e61

1240342113 has 8 divisors (see below), whose sum is σ = 1654999488. Its totient is φ = 826289744.

The previous prime is 1240342111. The next prime is 1240342121. The reversal of 1240342113 is 3112430421.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1240342113 - 21 = 1240342111 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1240342113.

It is not an unprimeable number, because it can be changed into a prime (1240342111) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 146445 + ... + 154682.

It is an arithmetic number, because the mean of its divisors is an integer number (206874936).

Almost surely, 21240342113 is an apocalyptic number.

It is an amenable number.

1240342113 is a deficient number, since it is larger than the sum of its proper divisors (414657375).

1240342113 is a wasteful number, since it uses less digits than its factorization.

1240342113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 302503.

The product of its (nonzero) digits is 576, while the sum is 21.

The square root of 1240342113 is about 35218.4910664838. The cubic root of 1240342113 is about 1074.4358642368.

Adding to 1240342113 its reverse (3112430421), we get a palindrome (4352772534).

The spelling of 1240342113 in words is "one billion, two hundred forty million, three hundred forty-two thousand, one hundred thirteen".

Divisors: 1 3 1373 4119 301127 903381 413447371 1240342113