Base | Representation |
---|---|
bin | 1011010001111110101101… |
… | …1011000011010111110011 |
3 | 1121220202122122202022100221 |
4 | 2310133223123003113303 |
5 | 3111204402200233021 |
6 | 42214033142553511 |
7 | 2420060540110051 |
oct | 264375333032763 |
9 | 47822578668327 |
10 | 12403520321011 |
11 | 3a52337953506 |
12 | 1483a75a38897 |
13 | 6bc854460ac1 |
14 | 30c49550d1d1 |
15 | 16799d8dc241 |
hex | b47eb6c35f3 |
12403520321011 has 2 divisors, whose sum is σ = 12403520321012. Its totient is φ = 12403520321010.
The previous prime is 12403520320967. The next prime is 12403520321051. The reversal of 12403520321011 is 11012302530421.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12403520321011 - 211 = 12403520318963 is a prime.
It is not a weakly prime, because it can be changed into another prime (12403520321051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6201760160505 + 6201760160506.
It is an arithmetic number, because the mean of its divisors is an integer number (6201760160506).
Almost surely, 212403520321011 is an apocalyptic number.
12403520321011 is a deficient number, since it is larger than the sum of its proper divisors (1).
12403520321011 is an equidigital number, since it uses as much as digits as its factorization.
12403520321011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 12403520321011 its reverse (11012302530421), we get a palindrome (23415822851432).
The spelling of 12403520321011 in words is "twelve trillion, four hundred three billion, five hundred twenty million, three hundred twenty-one thousand, eleven".
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