12403931258881 has 2 divisors, whose sum is σ = 12403931258882. Its totient is φ = 12403931258880.

The previous prime is 12403931258869. The next prime is 12403931258899. The reversal of 12403931258881 is 18885213930421.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10094701510656 + 2309229748225 = 3177216^2 + 1519615^2 .

It is an emirp because it is prime and its reverse (18885213930421) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12403931258881 - 2³¹ = 12401783775233 is a prime.

It is a super-2 number, since 2×12403931258881² (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (12403931250881) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6201965629440 + 6201965629441.

It is an arithmetic number, because the mean of its divisors is an integer number (6201965629441).

Almost surely, 2^{12403931258881} is an apocalyptic number.

It is an amenable number.

12403931258881 is a deficient number, since it is larger than the sum of its proper divisors (1).

12403931258881 is an equidigital number, since it uses as much as digits as its factorization.

12403931258881 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3317760, while the sum is 55.

The spelling of 12403931258881 in words is "twelve trillion, four hundred three billion, nine hundred thirty-one million, two hundred fifty-eight thousand, eight hundred eighty-one".