12404343433 has 4 divisors (see below), whose sum is σ = 12405395728. Its totient is φ = 12403291140.

The previous prime is 12404343409. The next prime is 12404343547. The reversal of 12404343433 is 33434340421.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12404343433 - 2¹⁷ = 12404212361 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12404343395 and 12404343404.

It is not an unprimeable number, because it can be changed into a prime (12404343733) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 508263 + ... + 532108.

It is an arithmetic number, because the mean of its divisors is an integer number (3101348932).

Almost surely, 2^12404343433 is an apocalyptic number.

It is an amenable number.

12404343433 is a deficient number, since it is larger than the sum of its proper divisors (1052295).

12404343433 is a wasteful number, since it uses less digits than its factorization.

12404343433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1052294.

The product of its (nonzero) digits is 41472, while the sum is 31.

Adding to 12404343433 its reverse (33434340421), we get a palindrome (45838683854).

The spelling of 12404343433 in words is "twelve billion, four hundred four million, three hundred forty-three thousand, four hundred thirty-three".