Base | Representation |
---|---|
bin | 1011010010001001011111… |
… | …0100000010111100111111 |
3 | 1121221001010012222222020000 |
4 | 2310202113310002330333 |
5 | 3111231313103212142 |
6 | 42215232141325343 |
7 | 2420222316511251 |
oct | 264422764027477 |
9 | 47831105888200 |
10 | 12406412554047 |
11 | 3a535914a7a46 |
12 | 1484542566853 |
13 | 6bcbc57124b5 |
14 | 30c68b6a1cd1 |
15 | 167abc79514c |
hex | b4897d02f3f |
12406412554047 has 20 divisors (see below), whose sum is σ = 18724098276576. Its totient is φ = 8185674257280.
The previous prime is 12406412554033. The next prime is 12406412554099. The reversal of 12406412554047 is 74045521460421.
12406412554047 is a `hidden beast` number, since 1 + 2 + 4 + 0 + 6 + 41 + 25 + 540 + 47 = 666.
It is not a de Polignac number, because 12406412554047 - 223 = 12406404165439 is a prime.
It is a super-2 number, since 2×124064125540472 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 12406412553993 and 12406412554011.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12406412550047) by changing a digit.
It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 789505479 + ... + 789521192.
Almost surely, 212406412554047 is an apocalyptic number.
12406412554047 is a deficient number, since it is larger than the sum of its proper divisors (6317685722529).
12406412554047 is an equidigital number, since it uses as much as digits as its factorization.
12406412554047 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1579026780 (or 1579026771 counting only the distinct ones).
The product of its (nonzero) digits is 1075200, while the sum is 45.
The spelling of 12406412554047 in words is "twelve trillion, four hundred six billion, four hundred twelve million, five hundred fifty-four thousand, forty-seven".
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